Question 1 : find the average Turn Around Time and Waiting Time of
following processes using MLQS(MULTILEVEL QUEUE SCHDULING) process
scheduling algorithm? Consider the following processes with their
Arrival Time, Burst Time. Question criteria :
(1) There are three queue Q1, Q2, Q3
(2) In Q1 (sjf, non-preemptive), Q2(Round robin, timestamp=1),Q3(FCFS)
| Process | Arrival Time | Burst Time | Queue name |
|---|---|---|---|
| P1 | 0 | 8 | Q2 |
| P2 | 1 | 6 | Q1 |
| P3 | 1 | 4 | Q3 |
| P4 | 2 | 3 | Q2 |
| P5 | 2 | 1 | Q1 |
| P6 | 3 | 4 | Q2 |
| P7 | 3 | 1 | Q1 |
| P8 | 4 | 2 | Q2 |
Formula:
Turnaround Time (TAT) = Completion Time - Arrival Time
Waiting Time (WT) = Turnaround Time - Burst Time
Solution:
Gantt Chart
Calculations:
| Process | Completion Time | Turnaround Time (TAT) | Waiting Time (WT) |
|---|---|---|---|
| P1 | 25 | 25 | 17 |
| P2 | 7 | 6 | 0 |
| P3 | 29 | 28 | 24 |
| P4 | 20 | 18 | 15 |
| P5 | 8 | 6 | 5 |
| P6 | 22 | 19 | 15 |
| P7 | 9 | 6 | 5 |
| P8 | 17 | 13 | 11 |
Average Turnaround Time:
(25 + 6 + 28 + 18 + 6 + 19 + 6 + 13) / 8 = 15.125
Average Waiting Time:
(17 + 0 + 24 + 15 + 5 + 15 + 5 + 11) / 8 = 11.5
Question 2 : find the average Turn Around Time and Waiting Time of
following processes using MLQS(MULTILEVEL QUEUE SCHDULING) process
scheduling algorithm? Consider the following processes with their
Arrival Time, Burst Time. Question criteria :
(1) There are three queue Q1, Q2, Q3
(2) In Q1 (Priority scheduling, premptive), Q2(sjf, preemptive) ,
Q3(Round robin, timestamp=1)
| Process | Arrival Time | Burst Time | Queue Name | Priority |
|---|---|---|---|---|
| P1 | 0 | 8 | Q2 | |
| P2 | 1 | 6 | Q1 | 4 |
| P3 | 1 | 4 | Q3 | |
| P4 | 2 | 3 | Q2 | |
| P5 | 2 | 1 | Q1 | 1 |
| P6 | 3 | 4 | Q2 | |
| P7 | 3 | 1 | Q1 | 5 |
| P8 | 4 | 2 | Q2 |
Formula:
Turnaround Time (TAT) = Completion Time - Arrival Time
Waiting Time (WT) = Turnaround Time - Burst Time
Solution:
Gantt Chart
Calculations:
| Process | Completion Time | Turnaround Time (TAT) | Waiting Time (WT) |
|---|---|---|---|
| P1 | 25 | 25 | 17 |
| P2 | 8 | 7 | 1 |
| P3 | 29 | 28 | 24 |
| P4 | 14 | 12 | 9 |
| P5 | 3 | 1 | 0 |
| P6 | 18 | 15 | 11 |
| P7 | 9 | 6 | 5 |
| P8 | 11 | 7 | 5 |
Average Turnaround Time:
(25 + 7 + 28 + 12 + 1 + 15 + 6 + 7) / 8 = 12.625
Average Waiting Time:
(17 + 1 + 24 + 9 + 0 + 11 + 5 + 5) / 8 = 9
Question 3 : find the average Turn Around Time and Waiting Time of
following processes using MLQS(MULTILEVEL QUEUE SCHDULING) process
scheduling algorithm? Consider the following processes with their
Arrival Time, Burst Time. Question criteria :
(1) There are four queue Q1, Q2, Q3, Q4
(2) In Q1(Round robin, timestamp=1), Q2(Priority scheduling,
preemptive), Q3(sjf, preemptive), Q4(FCFS)
| Process | Arrival Time | Burst Time | Queue name | Priority |
|---|---|---|---|---|
| P1 | 0 | 6 | 2 | 2 |
| P2 | 2 | 1 | 1 | 1 |
| P3 | 6 | 4 | 2 | 3 |
| P4 | 10 | 6 | 3 | 7 |
| P5 | 18 | 12 | 4 | 8 |
| P6 | 24 | 4 | 1 | 10 |
| P7 | 26 | 3 | 1 | 12 |
| P8 | 32 | 8 | 2 | 5 |
| P9 | 36 | 6 | 2 | 4 |
| P10 | 40 | 10 | 3 | 6 |
Formula:
Turnaround Time (TAT) = Completion Time - Arrival Time
Waiting Time (WT) = Turnaround Time - Burst Time
Solution:
Gantt Chart
Calculations:
| Process | Completion Time | Turnaround Time (TAT) | Waiting Time (WT) |
|---|---|---|---|
| P1 | 7 | 7 | 1 |
| P2 | 3 | 1 | 0 |
| P3 | 11 | 5 | 1 |
| P4 | 17 | 7 | 1 |
| P5 | 61 | 43 | 31 |
| P6 | 31 | 7 | 3 |
| P7 | 29 | 3 | 0 |
| P8 | 46 | 14 | 6 |
| P9 | 42 | 6 | 0 |
| P10 | 56 | 16 | 6 |
Average Turnaround Time:
(7 + 1 + 5 + 7 + 43 + 7 + 3 + 14 + 6 + 16) / 10 = 10.9
Average Waiting Time:
(1 + 0 + 1 + 1 + 31 + 3 + 0 + 6 + 0 + 6) / 10 = 4.9